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The energy in the earth state of a hydrogen atom is -13.6 ev. So the energy in the second excited state of he + ion is _____ ev.


aditibhagora2804 31st Aug, 2021
Answer (1)
Aditya 31st Aug, 2021

Hi aspirant,

For second excited state:

n=3 , We know that energy of a particle in an energy level is given by -13.6*z^2/n^2.

Therefore the energy of He+ ion  in second excited stage is: -13.6*2^2/3^2 = -54.4/9 = -6.04 eV.

Note- For helium, atomic number (z=2)

Hope it helps!!


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