The equation of the parabola whose vertex and focus lie on the axis of X at a distance a and b from origin respectively is
Answer (1)
20th Dec, 2019
Hii,
The answer for this will be y^2 = 4(b−a)(x−a) .
we'll get this equation after undertaking the following steps:
Given, Vertex A is (a,0)
Focus is (b,0)
Distance between vertex and focus AS = b−a=A (say)
So, the equation of parabola with vertex at
(a,0)
is
(y−0)^2 = 4A(x−a)(y−0)^2 = 4A(x−a)
= (y−0)^2 = 4(b−a)(x−a)⇒(y−0)^2 = 4(b−a)(x−a)
= y^2 = 4(b−a)(x−a)
= y^2 = 4(b−a)(x−a)
Hope this helps.
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