Question : The height of a cylinder is 45 cm. If the circumference of its base is 132 cm, then what is the curved surface of this cylinder? (use $\pi=\frac{22}{7}$)
Option 1: 6360 cm2
Option 2: 6270 cm2
Option 3: 5720 cm2
Option 4: 5940 cm2
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Correct Answer: 5940 cm 2
Solution : Given: The height of a cylinder is 45 cm. The circumference of the base of the cylinder = $2\pi r$ The curved surface of the cylinder = $2\pi rh$ Where $r$ and $h$ are the radius and height. The circumference of its base is 132 cm. ⇒ $2\times \frac{22}{7}\times r=132$ ⇒ $r=21$ cm The curved surface of the cylinder = $2\times \frac{22}{7} \times 21\times 45=44 \times 135=5940$ cm 2 Hence, the correct answer is 5940 cm 2 .
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