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Question : The height of an equilateral triangle is $9 \sqrt{3} \mathrm{~cm}$. What is the area of this equilateral triangle?

Option 1:  $92 \sqrt{3} \mathrm{~cm}^2$

Option 2: $67 \sqrt{3} \mathrm{~cm}^2$

Option 3: $49 \sqrt{3} \mathrm{~cm}^2$

Option 4: $81 \sqrt{3} \mathrm{~cm}^2$


Team Careers360 1st Jan, 2024
Answer (1)
Team Careers360 20th Jan, 2024

Correct Answer: $81 \sqrt{3} \mathrm{~cm}^2$


Solution : Let the sides of the equilateral triangle be $a$, then its height = $\frac{a\sqrt3}{2}$
⇒ $9\sqrt3 = \frac{a\sqrt{3}}{2}$
$\therefore a = 18$ cm
Now, the area of the triangle
= $\frac{a^2\sqrt3}{4}$
= $\frac{18×18×\sqrt3}{4}$
= $81 \sqrt{3} \mathrm{~cm}^2$
Hence, the correct answer is $81 \sqrt{3} \mathrm{~cm}^2$.

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