Question : The height of an equilateral triangle is $9 \sqrt{3} \mathrm{~cm}$. What is the area of this equilateral triangle?
Option 1: $92 \sqrt{3} \mathrm{~cm}^2$
Option 2: $67 \sqrt{3} \mathrm{~cm}^2$
Option 3: $49 \sqrt{3} \mathrm{~cm}^2$
Option 4: $81 \sqrt{3} \mathrm{~cm}^2$
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Correct Answer: $81 \sqrt{3} \mathrm{~cm}^2$
Solution : Let the sides of the equilateral triangle be $a$, then its height = $\frac{a\sqrt3}{2}$ ⇒ $9\sqrt3 = \frac{a\sqrt{3}}{2}$ $\therefore a = 18$ cm Now, the area of the triangle = $\frac{a^2\sqrt3}{4}$ = $\frac{18×18×\sqrt3}{4}$ = $81 \sqrt{3} \mathrm{~cm}^2$ Hence, the correct answer is $81 \sqrt{3} \mathrm{~cm}^2$.
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Question : If the side of an equilateral triangle is 16 cm, then what is its area?
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