Question : The interior angle of a regular polygon exceeds its exterior angle by 108$^\circ$. The number of the sides of the polygon is:
Option 1: 12
Option 2: 16
Option 3: 14
Option 4: 10
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Correct Answer: 10
Solution : Given that the interior angle of a regular polygon exceeds its exterior angle by 180$^\circ$. For a regular polygon, each exterior angle = $\frac{360^\circ}{n}$ And each interior angle = $\frac{180^\circ\times (n-2)}{n}$ So, $\frac{180^\circ\times (n-2)}{n}-\frac{360^\circ}{n}=108^\circ$ Or, $180^\circ\times n-108^\circ\times n=720^\circ$ Or, $n=10$ Hence, the correct answer is 10.
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