the number of values of x in the interval the number of values of X in the interval 0 2 3 5 satisfy the equation 2 sin square x + 5 sin x - 3 = 0 equal zero
Answer (1)
8th May, 2020
We will factorise the equation : 2(sin^2)x + 5sinx-3 =0
2(sin^2)x + 6sinx-sinx -3= 2sinx(sinx+3)-1(sinx+3)=0
Therefore we get 2 values of sinx,
sinx=1/2, -3
Since sinx can only lie in the interval [-1,1], we will only consider 1/2 as the solution, therefore number of solutions=1
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