Question : The population of a certain village increases by 5% annually. Its present population is 8200. After two years the population will be (approximately):
Option 1: 9200
Option 2: 9246
Option 3: 9040
Option 4: 9161
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Correct Answer: 9040
Solution : Present population, $P$ = 8200 Time, $t$ = 2 years Rate, $r$ = 5% Population after $t$ years at the rate of $r$ % = $P(1+\frac{r}{100})^{t}$ = $8200(1+\frac{5}{100})^{2}$ = $8200(\frac{21}{20})^{2}$ = $8200×\frac{441}{400}$ = $9040.5\approx 9040$ Hence, the correct answer is 9040.
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