Question : The radii of the ends of a frustum of a cone 7 cm high are 5 cm and 3 cm. Find its volume correct to one decimal place. (Use $\pi=\frac{22}{7}$)
Option 1: 345.6 cm3
Option 2: 359.3 cm3
Option 3: 379.3 cm3
Option 4: 369.3 cm3
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Correct Answer: 359.3 cm 3
Solution : Given, a bigger radius, $R$ = 5 cm Smaller radius, $r$ = 3 cm Height, $h$ = 7 cm Volume of frustum = $\frac{1}{3}\pi(R^2+Rr+r^2)h$ = $\frac{1}{3}\times\frac{22}{7}\times(5^2+5\times 3+3^2)\times 7$ = $\frac{1}{3}\times 22\times 49$ = 359.3 Hence, the correct answer is 359.3 cm 3 .
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