the radius of the Bohr orbit in the ground state of hydrogen atom is 0.5 angstrom. the radius of the orbit of the electron in the third excited state of He+ will be
Answers (2)
11th Jan, 2020
Hello
See as we know radius of stationary state of bohr model is given by
Rn=n square× Armstrong
So, for helium it will be
Rn=4×0.5×10^-10
= 2.0×10^-10
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11th Jan, 2020
Hello,
We know that,
For nth Bohr's orbit, the formula of radius is,
r = ( 0.529 n^2 ) / Z
So, for third excited state of He+ ion,
n = 4 and Z = 2
So, r = ( 0.529 x 4^2 ) / 2
So, r = 8.464 / 2
So, r = 4 Å
So, Radius of Orbit of the electron in the third excited state of He+ will be 4 Å
Best Wishes.
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