Question : The table given below shows the marks obtained by boys and girls in different subjects.
L1 = The difference between marks obtained by boys and girls in all subjects. L2 = The value of the average of marks obtained by boys in C, D, and E. What is the value of (L1 – L2)?
Option 1: 40
Option 2: 20
Option 3: 10
Option 4: 50
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Correct Answer: 20
Solution : The difference between marks obtained by boys and girls in all subjects, L1 = (60 + 80 + 140 + 120 + 100) – (120 + 100 + 40 + 60 + 40) ⇒ L1 = 500 – 360 = 140 $\text{Average}=\frac{\text{Sum of all the values}}{\text{Number of all the values}}$ The value of the average of marks obtained by boys in C, D, and E = L2 = $\frac{140+120+100}{3}= \frac{360}{3}$ = 120 The value of L1 – L2 = 140 – 120 = 20 Hence, the correct answer is 20.
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