Question : The table given below shows the number of sharpeners sold by two shopkeepers A and B in 5 months.
$P1$ = The total number of sharpeners sold by A. $P2$ = The total number of sharpeners sold by B. What is the value of $\frac{P1}{P2}$?
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
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Correct Answer: 1
Solution : As per the given graph, $P1$ (total sharpeners sold by A) = 200 + 190 + 170 + 165 + 155 = 880 $P2$ (total sharpeners sold by B) = 155 + 160 + 210 + 180 + 175 = 880 So, the value of $\frac{P1}{P2}$ = $\frac{880}{880}$ = 1 Hence, the correct answer is 1.
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