2368 Views

The time of reverberation of an empty hall is 1.5sec with 500 audience present in the hall,the time of reverberation falls to 1.4sec.Find the number of persons in the hall if the reverberations time falls to 1.312sec....Plsss answer this question...


Adithya Kiran 11th Sep, 2019
Answer (1)
vishal sharma 30th Oct, 2020

Hello Adithya

According to Sabine formula, time of reverberation t = (0.16*V)/(A*α)

Thus, For an empty room, 1.5 = (0.16*V)/(S*α)………………..[1]

Lets assume the volume of 1 person to be 1m 3

With 500 persons, 1.4 = 0.16(V – 500)/S α…………….[2]

From eq[1], S* α = 0.16V/ 1.5

Thus, on solving eq[2] , we get 1.4 = 1.5 – (500* 0.16/S α)

  • 1.5 -1.4 = 500* 1.5 / V
  • 0.1 = 750/V
  • V = 7500

For t = 1.312, let the number of people be n

=> 1.312 = 0.16(V – n)/S α

=> 1.312 = 1.5 – (n* 1.5/7500)

=>  n/5000 = 1.5- 1.312

=> n = 5000 * 0.188

=>  n = 940

Hence, there are 940 persons.


Related Questions

Chanakya University M.sc Admi...
Apply
Scholarships Available | Top notch Faculty
Ashoka University - Young Ind...
Apply
Interdisciplinary Courses | 80+ Prestigious Scholarship Awardees
Amity University | B.Sc Admis...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
UPES B.Sc Admissions 2025
Apply
Ranked #46 amongst Universities in India by NIRF | Last Date to Apply: 28th Feb | LIMITED EARLY ACCEPTANCE SCHOLARSHIPS ON OFFER
Sanskriti University M.Sc Adm...
Apply
Best innovation and research-driven university of Uttar Pradesh
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books