Question : The value of $\lambda$ for which the expression $x^3 + x^2 - 5x + \lambda$ will be divisible by $(x-2)$ is:
Option 1: 2
Option 2: – 2
Option 3: – 3
Option 4: 4
New: SSC MTS 2024 Application Form OUT; Direct Link
Don't Miss: Month-wise Current Affairs | Upcoming Government Exams
New: Unlock 10% OFF on PTE Academic. Use Code: 'C360SPL10'
Correct Answer: – 2
Solution : Given: $(x - 2)$ is a factor of the polynomial $P(x)= x^3 + x^2 - 5x + \lambda$ So, $P(2)=0$ ⇒ $8 + 4 - 10 + λ = 0$ ⇒ $λ + 2 = 0$ ⇒ $λ= -2$ Hence, the correct answer is – 2.
Application | Cutoff | Selection Process | Preparation Tips | Eligibility | Exam Pattern | Admit Card
Question : If $x=-1$, then the value of $\frac{1}{x^{99}}+\frac{1}{x^{98}}+\frac{1}{x^{97}}+\frac{1}{x^{96}}+\frac{1}{x^{95}}+\frac{1}{x^{94}}+\frac{1}{x}-1$ is:
Question : What is the value of $\frac{44–13+17–21+45–24}{12 \text { of } 4–3 \times 4–6 \times 2}$?
Question : What is the value of $x$, if $\frac{1}{2}$ of 20 + $\frac{1}{4}$ of 28 – $\frac{1}{4}$ of $x$ = 10?
Question : Directions: After interchanging which two signs will the value of the given expression be 37? 27 + 3 ÷ 81 × 93 – 57
Question : $x$ varies inversely as the square of $y$. Given that $y=2$ for $x=1$, the value of $x$ for $y=6$ will be equal to:
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile