Question : The value of $\frac{40+\frac{3}{4} \text { of } 32}{37+\frac{3}{4} \text { of }(34-6)}$ is:
Option 1: $1 \frac{3}{29}$
Option 2: $-1 \frac{3}{29}$
Option 3: $1 \frac{9}{29}$
Option 4: $2 \frac{3}{29}$
Correct Answer: $1 \frac{3}{29}$
Solution :
Given: $\frac{40+\frac{3}{4} \text { of } 32}{37+\frac{3}{4} \text { of }(34-6)}$
= $\frac{40+24}{37+\frac{3}{4} \text { of }(28)}$
= $\frac{64}{37+21}$
= $\frac{64}{58}$
= $\frac{32}{29}$
= $1\frac{3}{29}$
Hence, the correct answer is $1\frac{3}{29}$.
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