116 Views

The volume of largest possible right circular cylinder that can be increased in sphere of radius root3 is


JayaShankar Mangapati 18th Apr, 2020
Answers (2)
lubhan cherwoo 18th Apr, 2020
Hi,

r^2=R^2-(h^2)/4
Vc=pie r^2 h
=Pie(R^2-(h^2)/4)h

dV/dh=pie R^2 - (3pie h^2)/4
For R=root 3
dV/dh= 3pie - (3pie h^2)/4
For maximum or minimumvolume,dV/dh=0
h=2

Also,dhdVchanges sign from positive to negativein the neighbourhood ofh=2. Hence,h=2is a maximum point.
r= root 2
V=4 pie cubic units
Smrity 18th Apr, 2020

Hey,

it is given radius of sphere is root3.

we know that,

r^2= R^2 - ((h^2)/4)


Vc= pi*r^2*h = pi*(R^2-((h^2)/4)h=pi*R^2*h-(pi*h^3/4)

Now

dV/dh=pi*R62-3*pi*h^2/4

for maximum or minimum volume we know that dV/dh=0

hence putting the value of dV/dh and R=root 3 in above equation we get,

h=2

if h=2 then

r= root 2

and volume is equal to 4pi cubic units

which is the required answer.

I hope this helps.

all the best!





Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
TAPMI MBA 2025 | Technology M...
Apply
MBA Admission Open in Technology Management and AI & Data Science | NAAC A++ | Institution of Eminence | Assured Scholarships
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
East Point College | MBA Admi...
Apply
NBA Accredited | AICTE Approved
Chitkara University MBA Admis...
Apply
NAAC A+ Accredited | 100% CAMPUS RECRUITMENT
Amity University Noida B.Tech...
Apply
Among Top 30 National Universities for Engineering (NIRF 2024) | 30+ Specializations
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books