Question : Three angles of a triangle are $(x-15^{\circ}),(x+45^{\circ}),$ and $(x+60^{\circ})$. Identify the type of triangle.
Option 1: Obtuse angle triangle
Option 2: Right angle triangle
Option 3: Isosceles triangle
Option 4: Equilateral triangle
New: SSC CHSL Tier 2 answer key released | SSC CHSL 2024 Notification PDF
Recommended: How to crack SSC CHSL | SSC CHSL exam guide
Don't Miss: Month-wise Current Affairs | Upcoming government exams
Correct Answer: Right angle triangle
Solution :
Given: Angles of the triangles is $(x-15^{\circ}),(x+45^{\circ}),$ and $(x+60^{\circ})$.
Let $\angle A =(x-15^{\circ}) $
$\angle B =(x+45^{\circ}) $
$\angle C =(x+60^{\circ}) $
We know that the sum of the angles of a triangle is $180^\circ$.
So, $(x-15^{\circ})+(x+45^{\circ})+(x+60^{\circ}) = 180^{\circ}$
⇒ $3x+90^{\circ}=180^{\circ}$
⇒ $x=30^{\circ}$
Putting the values we get:
$\angle A =(30-15^{\circ})=15^{\circ} $
$\angle B =(30+45^{\circ})=75^{\circ} $
$\angle C =(30+60^{\circ}) =90^{\circ}$
Since one of the angles is $90^{\circ}$,
⇒ The triangle is right-angled.
Hence, the correct answer is the Right angle triangle.
Related Questions
Know More about
Staff Selection Commission Combined High ...
Result | Eligibility | Application | Admit Card | Answer Key | Preparation Tips | Cutoff
Get Updates Brochure
Your Staff Selection Commission Combined Higher Secondary Level Exam brochure has been successfully mailed to your registered email id “”.
Upcoming Exams
Trending Articles around SSC CHSL
