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Question : Two circles C1 and C2 touch each other internally at P. Two lines PCA and PDB meet the circles C1 in C, D, and C2 in A, B respectively. If $\angle$BDC=120°, then the value of $\angle$ABP is equal to

Option 1: 60°

Option 2: 80°

Option 3: 100°

Option 4: 120°


Team Careers360 8th Jan, 2024
Answer (1)
Team Careers360 19th Jan, 2024

Correct Answer: 60°


Solution :
Given $\angle$BDC = 120°
Then, $\angle$CDP = 180° – 120° = 60°
Here, CD || AB
So, $\angle$CDP = $\angle$ABP
$\therefore$ $\angle$ABP = 60°
Hence, the correct answer is 60°.

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