two rods of same length having conductivities 60 Wmk, 40 Wmk and areas 0.2 m*2 ,0.3 m*2 are connected in parallel to each other .The effective conductivity of the combination is
Answer (1)
13th Jan, 2020
Hello,
We know that,
Equivalent Conductivity for parallel combination is given as,
Keq. = ( K1.A1 + K2.A2 ) / A1 + A2
where, K is the Conductivity and A is the Area
So, from given data, A1 = 0.2 and A2 = 0.3
Also, K1 = 60 and K2 = 40
So, Keq. = [ ( 60 x 0.2 ) + ( 40 x 0.3 ) ] / ( 0.2 + 0.3 )
So, Keq. = 24 / 0.5
So, Keq. = 48 Wmk
Hence, the effective conductivity is 48 Wmk
Best Wishes.
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