Question : Two trains are moving in opposite directions at speeds of 43 km/h and 51 km/h, respectively. The time taken by the slower train to cross a man sitting in the faster train is 9 seconds. What is the length (in metres) of the slower train?
Option 1: 235
Option 2: 338.4
Option 3: 470
Option 4: 940
Latest: SSC CGL preparation tips to crack the exam
Don't Miss: SSC CGL complete guide
Correct Answer: 235
Solution :
Given:
The speed of two trains = 43 km/h and 51 km/h
They are moving in opposite directions.
⇒ Relative speed = (43 + 51) km/h = 94 km/h
⇒ Relative speed in metre/second $= 94 × \frac{5}{18}$ metre/second
⇒ Distance covered by the train in 9 seconds $= 94 × \frac{5}{18} × 9= 235$ m
Since this is the distance covered in crossing the man.
So, the length of the slower train is 235 metres.
Hence, the correct answer is 235.
Related Questions
Know More about
Staff Selection Commission Combined Grad ...
Answer Key | Eligibility | Application | Selection Process | Preparation Tips | Result | Admit Card
Get Updates Brochure
Your Staff Selection Commission Combined Graduate Level Exam brochure has been successfully mailed to your registered email id “”.
