Question : What is the simplified value of $\frac{33}{(6–\sqrt3)}$?
Option 1: $6+\sqrt3$
Option 2: $6-\sqrt3$
Option 3: $12+\sqrt3$
Option 4: $12-\sqrt3$
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Correct Answer: $6+\sqrt3$
Solution : $\frac{33}{(6–\sqrt3)}$ $=\frac{33}{(6–\sqrt3)}×\frac{(6+\sqrt3)}{(6+\sqrt3)}$ $=\frac{33(6+\sqrt3)}{33}$ $=(6+\sqrt3)$ Hence, the correct answer is $(6+\sqrt3)$.
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