Question : What is the smallest three-digit number when divided by 2, 3, and 4 leaving the remainder 1 in each case?
Option 1: 111
Option 2: 105
Option 3: 101
Option 4: 109
Answer (1)
5th Jan, 2024
Correct Answer: 109
Solution :
Smallest 3-digit number = 100
LCM of 2, 3, 4 = 12
100 = 12 × 8 + 4
Remainder = 1
$\therefore$ Required number = 100 + (12 – 4) + 1 = 108 + 1 = 109
Hence, the correct answer is 109.
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