Question : What is the value of $\frac{\frac{5}{6} \text { of } \frac{1}{3} \times \frac{12}{25}-\frac{1}{3} \text { of } \frac{5}{6} \times \frac{18}{25}}{\frac{25}{12} \text { of } \frac{1}{6} \times \frac{2}{5}+\frac{3}{8} \text { of } \frac{12}{25} \times \frac{5}{6}}$?
Option 1: $-\frac{3}{13}$
Option 2: $-\frac{5}{13}$
Option 3: $-\frac{8}{25}$
Option 4: $-\frac{3}{25}$
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Correct Answer: $-\frac{3}{13}$
Solution :
Given: $\frac{\frac{5}{6} \text { of } \frac{1}{3} \times \frac{12}{25}-\frac{1}{3} \text { of } \frac{5}{6} \times \frac{18}{25}}{\frac{25}{12} \text { of } \frac{1}{6} \times \frac{2}{5}+\frac{3}{8} \text { of } \frac{12}{25} \times \frac{5}{6}}$
$=\frac{\frac{5}{18}\times \frac{12}{25}- \frac{5}{18} \times \frac{18}{25}}{\frac{25}{72} \times \frac{2}{5}+\frac{9}{50} \times \frac{5}{6}}$
$=\frac{\frac{2}{15}-\frac{1}{5}}{\frac{5}{36}+\frac{3}{20}}$
$=\frac{\frac{2-3}{15}}{\frac{25+27}{180}}$
$=\frac{-1}{15}\times \frac{180}{52}$
$=-\frac{3}{13}$
Hence, the correct answer is $-\frac{3}{13}$.
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