Question : What is the value of $\frac{91+13 \text { of }(45 ÷ 21 × 14 ÷ 5) - 22 × 4}{(42 × 21 ÷ 168 × 2) - (66 \text { of } 15 ÷ 90)}$?
Option 1: – 172
Option 2: – 81
Option 3: –162
Option 4: –144
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Correct Answer: –162
Solution : $\frac{91+13 \text { of }(45 ÷ 21 × 14 ÷ 5) - 22 × 4}{(42 × 21 ÷ 168 × 2) - (66 \text { of } 15 ÷ 90)}$ = $\frac{91+13 \text { of }6 - 22 × 4}{10.5 - 11}$ = $\frac{91+ 78 - 88}{-0.5}$ = $\frac{81}{-0.5}$ = ${- 162}$ Hence, the correct answer is –162.
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