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(X+Y) whole square +(Y+Z)whole square +(Z+X)whole square when X+Y+Z=2 and XY +YZ+ ZX= 1


Aaditya Jha 23rd Apr, 2019
Answer (1)
Aaryan Sood 24th Apr, 2019

Hey Aaditya,

Here’s the solution to the asked problem:-

(X+Y)^2 = X^2 + Y^2 +2XY

(Y+X)^2 = Y^2 + Z^2 + 2YZ

(Z+X)^2 = Z^2 + X^2 +2ZX

(X+Y+Z)^2 = X^2 + Y^2 + Z^2 + 2(XY + YZ + ZX)

Use the above equations to calculate the value. 4th equation could be used for calculation of X^2 + Y^2 + Z^2 and could be substituted in the initial 3 equations for the desired results.

Hope this helps.

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