A bag contains 5 red and 3 black balls and another bag contains 2 red and 6 black balls. Two balls are drawn at random (without replacement) from one of the bags and both are found to be red. Find the probability that balls are drawn from the first bag.
Answer (1)
10th May, 2021
hello Aspirant
I hope you are doing good. This question can be answered by applying base theorem
probabibility ofn choose 1st bag =1/2
probability of chossing 2nd bag=1/2
Probability of getting red ball from bag 1=5/8
Probability of getting red ball from bag2=1/4
Proability of having red ball form bag1
= (1/2*5/8)/((1/2*5/8)+(1/2*1/4))
Solve this now by your own that will be your required answer
Hope you found this answer helpful. Good luck for your future
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