Bag I contains 4 red and 2 green balls and Bag II contains 3 red and 5 green balls. One ball is transferred at random from Bag I to Bag II and then a ball is drawn at random from Bag II. The ball so drawn is found to be green in colour. Find the probability that
Answer (1)
13th Feb, 2022
Hi there,
Let E1 and E2 respectively denote the events that a red ball is transferred from a bag 1 to 2 and a green ball is transferred from bag 1 to bag 2
P(E1)=4/6
P(E2)=2/6
LET A be the event that the ball drawn is green
(i) when a red ball is transferred from bag 1 to 2
P(A/E1)=5/9
2) when a green ball is transferred from bag 1 to 2
P(A/E2)=6/9
P(E2)/A= p(E2) p(A/E2)/ p(E1) p(A/E1) + p(E2)p(A/E2)
=3/8
Hope it helps you
Good luck!
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