solution of a bag contains 5 white, 7 red, 8 black balls. Four balls are drawn one by one with replacement. what is the probability that at least one is white
Dear Aspirant,
the probability that at least one is white is, In a trial the probability of selecting a white ball is 5/20
So, in 4 trials the probability that at least one is white is, S electing a white and then choosing from the rest,
⇒ 1- 81/256that no ball is white
is175/256
Hello Palak,
The solution to your question is quite simple. I guess this is a question from the Probability chapter. The answer ot your question is 0.6836 or simply 68.36%.
The solution can be seen as:
1-((3/4)^4)=0.683 where 3/4 is the required probbility in each pick.
Hope this Helps