a block of mass M id pulled along a horizontal frictionless surface by a rope of mass m .if force P is applied at the free end of the rope the force exerted by the role on block is
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Given force of rope at free end = P
Given Mass of block = M
Given mass of rope = m
Let the force exerted by the rope on block = T
Let the common acceleration be = a
For block,(force),, T=Ma
for rope ,(force) ,,P - T=ma
=P-Ma = ma
=P=(M+m)a
=a=P/(M+m)
We have to find T,,,, So,,T=M*(a)
= T=MP/(M+m)
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