470 Views

a block of mass M is placed on an ideal spring and equilibrium the spring is compressed by x loot in equilibrium. if the spring is further compressed by 2x then find the time period of oscillation


1111rajneesh1111 21st Jan, 2021
Answer (1)
Ayush 21st Jan, 2021

Hello candidate,

In spring mass system, the time period refers to the time required for the spring to regain its original shape after compressing or extending from its natural length.

The expression for time period is given by the formula T=2π×√m/k, which is clearly independent of the the extension produced. So, the time period of oscillation will remain same irrespective of the extension being extended to 2x.

Hope it helps!!

Related Questions

Chandigarh University Admissi...
Apply
Ranked #1 Among all Private Indian Universities in QS Asia Rankings 2025 | Scholarships worth 210 CR
Amity University, Noida Law A...
Apply
700+ Campus placements at top national and global law firms, corporates, and judiciaries
Amity University, Noida BBA A...
Apply
Ranked amongst top 3% universities globally (QS Rankings)
UPES | BBA Admissions 2025
Apply
#41 in NIRF, NAAC ‘A’ Grade | 100% Placement, up to 30% meritorious scholarships | Last Date to Apply: 28th Feb
MAHE Manipal M.Tech 2025
Apply
NAAC A++ Accredited | Accorded institution of Eminence by Govt. of India | NIRF Rank #4
Sanskriti University LLM Admi...
Apply
Best innovation and research-driven university of Uttar Pradesh
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books