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A car moves in a circle at the constant speed of 50m/s and complete one revolution in 40s.Determine the magnitude of acceleration of the car


Padmakar Jagtap 3rd Aug, 2019
Answer (1)
Anshika Srivastava 3rd Aug, 2019

Hello Padmakar!

We know that, distance = speed*time

So, d = 50*40 = 2000m

d = 2*3.14*r (circumference of the circle)

=> 2000=2*3.14*r

On calculating, r = 318.47 m

In this case, required acceleration will be centripetal acceleration.

So, a = (v*v)/r

a = (50*50)/318.47

a = 7.85m/s^2

Hope this helps.

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