809 Views

A copper disc of radius 0.1 M is rotating about its nature at least Axis with 10 RPS in a uniform magnetic field of 0.1 PVT is trained perpendicular to the field the EMF induced across the radius of the disc is


Vyshnavi.G 11th Nov, 2019
Answer (1)
Mahima Shukla 17th Dec, 2019

HIi,

The answer for this question will be π/10.

For solving this you can use the formula  Ein = 1/2BwR^2

where Ein denotes  induced emf, B is the magnetic field, w(omega) denotes angular frequency of disc and R is the radius of disc.

Here, B =  0.1, R = 0.1 and

w(omega) = 10rps = 20 pi radian/sec.

Therefore, Ein = 1/2 × 0.1 × 20π × (0.1)²

= 1/2 × 20π × 0.01 = π/10 V

Hope this helps.


Related Questions

UPES Integrated LLB Admission...
Apply
Ranked #28 amongst Institutions in India by NIRF | Ranked #1 in India for Academic Reputation by QS University Rankings | 16.6 LPA Highest CTC
SLAT 2025 - The Symbiosis Law...
Apply
Conducted by Symbiosis International (Deemed University) | Ranked #5 in Law by NIRF | Ranked #2 among best Pvt Universities by QS World Rankings
Jindal Global Law School Admi...
Apply
Ranked #1 Law School in India & South Asia by QS- World University Rankings | Merit cum means scholarships
Symbiosis Law School Pune Adm...
Apply
NAAC A++ Accredited | Ranked #5 by NIRF
Nirma University Law Admissio...
Apply
Grade 'A+' accredited by NAAC
ISBR Business School PGDM Adm...
Apply
180+ Companies | Highest CTC 15 LPA | Average CTC 7.5 LPA | Ranked as Platinum Institute by AICTE for 6 years in a row | Awarded Best Business Scho...
View All Application Forms

Download the Careers360 App on your Android phone

Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile

150M+ Students
30,000+ Colleges
500+ Exams
1500+ E-books