a gas at 10c temperature and 1.013 ×10^3 pa pressure is compressed adiabatically to half of it's volume. if the ration of specific heats of the gas is 1:4 , what is it's final temperature
Answer (1)
17th Jul, 2020
First Convert Temp deg Celsius to kelvin
T1 = 10deg c + 273K = 283 k
Volume is half then
V2 = V1/2
Gama is 1.4
So equation is T1 V1^gama-1 = T2 V2^gama -1
then T2 = T1 x (v1/v2)^gama-1
so T2 = 283 x (V1/(v1/2))^1.4-1
T2 = 283 x 2^0.4
T2 = 373.42K
to Kelvin to deg cel
T2 = 100.42 deg cel
Hope its Help!!
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