a uniform rod of length l, young's modulus Y and cross section A, placed on a smooth horizontal table, is pulled by a force F applied parallel to the rod at one end. the other end of the rod is free.Find the strain energy stored in the rod.
Answer (1)
25th Dec, 2019
Hello,
If the table was rough i.e. had friction, the static friction force would have adjusted itself to match the external force F and hence two equal and opposite forces would have caused stress to occur in the rod. But here the table is smooth, so I don't know what other force will oppose the external force and how stress will be produced.
I'm not sure of this but if I assume that atomic force of attraction would oppose the external force and the rod is reduced to the center of mass(at a distance of l2l2 ), the following strain energy would be stored in the rod:-
U=12Y(stress)2Al2U=12Y(stress)2Al2
U=12Y(FA)2Al2U=12Y(FA)2Al2
U=F2l4YA
Hope this helps, Good luck.
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