an ideal gas is enclosed in a cylinder at pressure of 2atm and temperature,300k the mean time between two successive collisions is 6×10^-8.If the pressure is doubled and temperature is increased to 500k,the mean time between two successive collisions will be close to?
Answer (1)
Student Expert
28th Jun, 2021
Hi Aspirant!
As we know that,
t is directly proportional to (Volume/Velocity)
=> Volume is directly proportional to (T/P)
Therefore, t is directly proportional to [(sqr root T)/ P ]
Now, t1 / (6x10^-8) = [(sqr root 500)/2P ] * [P / (sqr root 300) ]
=> t1 = 3.8x10^-8
=> t1 ~= 4x10^-8 seconds
Hope it helps to clear your dilemma, thankyou!
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