calculate the De Broglie wavelength associated with the electron in the second excited state of hydrogen atom in ground state energy of the hydrogen atom is 13.6 electron volt
Answer (1)
8th Jul, 2021
Hello candidate,
This given question its mentioned that an electron is in the second excited States which makes the principal quantum Number equal to 3 and has to get the excited to the ground state which makes the second principal quantum number equal to 1 between which the transition is to take place.
The formula for De broglie's wavelength is given by 1/wavelength= R*(1-1/9), where the R can be referred as Rydberg's constant. So, the value of lambda in terms of rydberg constant is equal to 9/8R.
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