Galileo writes that for angles of projection of a projectile at angles (45+alpha) and (45-alpha) the horizontal ranges describe by the pro
Answer (1)
Student Expert
9th Jul, 2019
Dear Karsang,
For complementary angles, range will be same. Therefore,
For angle (45°-θ), R = u2sin(90° - 2θ)/g = u2 cos 2θ/g
For angle 45°+θ), R = u2sin(90° + 2θ)/g = u2 cos 2θ/g
So, the ratio of the projectile is - 1:1
Thus answer is 1:1
All the best
Feel free to ask for any query
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