Question : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm. What is the radius (in cm) of the circumcircle of $\triangle$ ABC?
Option 1: 12.5
Option 2: 13
Option 3: 25
Option 4: 26
Correct Answer: 13
Solution : In $\triangle$ ABC, $\angle$ BCA = $90^{\circ}$, AC = 24 cm and BC = 10 cm AB 2 = AC 2 + BC 2 $AB = \sqrt{24^2 + 10^2} = \sqrt{576+100} = \sqrt{676} = 26$ cm Circumradius of $\triangle ABC = \frac{AB}{2} = \frac{26}{2} = 13$ cm Hence, the correct answer is 13.
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