Question : In an isosceles triangle PQR, $\angle$P = 130°, If I is the in-centre of the triangle, what is the value of $\angle$QIR?
Option 1: 130°
Option 2: 120°
Option 3: 155°
Option 4: 165°
Correct Answer: 155°
Solution : Given: $\angle$PQR = 130°, I is the incentre of the triangle. So, $\angle$QIR = $90°+\frac{\angle PQR}{2}=90°+\frac{130°}{2}=155°$ Hence, the correct answer is 155°.
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Question : Circum-centre of $\triangle PQR$ is O. If $\angle QPR=55^{\circ}$ and $\angle QRP=75^{\circ}$, What is the value (in degree) of $\angle OPR$?
Question : $\triangle \mathrm{ABC}$ and $\triangle \mathrm{DEF}$ are two triangles such that $\triangle \mathrm{ABC} \cong \triangle \mathrm{FDE}$. If AB = 5 cm, $\angle$B = 40° and $\angle$A = 80°, then which of the following options is true?
Question : In $\triangle \mathrm{ABC}, \angle \mathrm{A}=68^{\circ}$. If I is the incentre of the triangle, then the measure of $\angle B I C$ is:
Question : Internal bisectors of $\angle$ B and $\angle$ C of $\triangle$ ABC meet at O. If $\angle$ BAC = $80^{\circ}$, then the value of $\angle$ BOC is:
Question : If $\triangle$PQR is right-angled at Q, PQ = 12 cm and $\angle$PRQ = 30°, then what is the value of QR?
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