Question : $\triangle ABC$ is an isosceles triangle with AB = AC. If $\angle BAC=50^\circ$, then the degree measure of $\angle ABC$ is equal to:

Question : $ABC$ is an isosceles triangle with $AB = AC$, The side $BA$ is produced to $D$ such that $AB = AD$. If $\angle ABC = 30^{\circ}$, then $\angle BCD$ is equal to:

Question : It is given that $\triangle \mathrm{PQR} \cong \triangle \mathrm{MNY}$ and $PQ=8\ \mathrm{cm}, \angle Q = 55°$ and $\angle P = 72°$. Which of the following is true?

Question : It is given that $\triangle \mathrm{ABC} \cong \triangle \mathrm{FDE}$ and $\mathrm{AB}=5 \mathrm{~cm}, \angle \mathrm{B}=40^{\circ}$ and $\angle \mathrm{A}=80^{\circ}$. Then which of the following is true?

Question : In $\triangle \mathrm{CAB}, \angle \mathrm{CAB}=90^{\circ}$ and $\mathrm{AD} \perp \mathrm{BC}$. If $\mathrm{AC}=24 \mathrm{~cm}, \mathrm{AB}=10 \mathrm{~cm}$. then find the value of $AD$ (in cm).