Third Bohe orbit corresponds to principle quantum number, n = 3. Now, energy of an electron in n = n is En= - 13.6/ n^2 eV for hydrogen atom. Now, in Bohr's theory we come across the result:En= (1/2) ( potential energy). Therefore, (1/2)(potential energy )=-(13.6/9)eV. Therefore, potential energy =-27.2/9 eV……………..(1) Now, kinetic energy K = total energy - potential energy Then, K=-13.6/9-(-27.2/9)=13.6/9 eV.
Regular exam updates, QnA, Predictors, College Applications & E-books now on your Mobile