The 1 mol of an ideal gas is compressed reversible from 1 bar to 5 bar at a constant temperature of 300 K. How much work is involved (in kJ)
Answer (1)
9th Nov, 2020
Hi Rohith,
The 1 mol of an ideal gas is compressed reversible from 1 bar to 5 bar at a constant temperature of 300 K.
This is a reversible & isothermal process.
Here T=300K.
work done =−nRT*ln(P1/P2)
n=1 mole
P1=1bar P2=5bar
R=8.3144598 J. mol - 1 . K - 1 .
So,
W=-2494.2*(-1.609)=4014.26 J
So work done is 4.01 kJ. Since this is a case of ideal gas, so the work done is positive.
Hope this helps!
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