Question : Two trains are moving in opposite directions at speeds of 43 km/h and 51 km/h, respectively. The time taken by the slower train to cross a man sitting in the faster train is 9 seconds. What is the length (in metres) of the slower train?
Option 1: 235
Option 2: 338.4
Option 3: 470
Option 4: 940
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Correct Answer: 235
Solution : Given: The speed of two trains = 43 km/h and 51 km/h They are moving in opposite directions. ⇒ Relative speed = (43 + 51) km/h = 94 km/h ⇒ Relative speed in metre/second $= 94 × \frac{5}{18}$ metre/second ⇒ Distance covered by the train in 9 seconds $= 94 × \frac{5}{18} × 9= 235$ m Since this is the distance covered in crossing the man. So, the length of the slower train is 235 metres. Hence, the correct answer is 235.
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