Question : What is the value of $\frac{99 \div 33+44 \div 11 \text { of } 4}{24 \div 12–4+3}$?
Option 1: 6
Option 2: 4
Option 3: 1
Option 4: 8
Answer (1)
24th Jan, 2024
Correct Answer: 4
Solution :
$\frac{99 \div 33+44 \div 11 \text { of } 4}{24 \div 12–4+3}$
$=\frac{99 \div 33+44 \div 44}{2–4+3}$
$=\frac{3+1}{5–4}$
$=4$
Hence, the correct answer is 4.
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