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Yes my college have all the necessary infrastructure and necessary laboratory facilities and necessary laboratory equipments and have good classrooms and they all used and well maintained and the living space is good and cleaned.
Yes it have a good infrastructure and food atmosphere in the campus. All are well maintained and useful for practicals and let's ur gain knowledge. The living space is clean but the food in hostel is not upto the mark.
Good infrastructure and nice lab facilities and buliding are. Build with nice architecture and good design and the campus is good and the having a nice atmosphere inside the college and have good libraries.
Hello,
Ashoka Senior Secondary School is a private school in Sirhind Mandi, Fatehgarh Sahib district, Punjab. It offers education from grades 6 to 12 and is located near the Sirhind bus stand.
The school focuses on academic excellence and overall development. It has an active presence on social media, where updates and events are shared. The institution is known for its disciplined environment and quality education, making it a preferred choice for students in the region.
Hope it helps !
Hello Kritika,
Admission to a specific section, such as Sec-A, Sec-B, or Sec-C, in Class 7 typically depends on the school's internal policies and the availability of seats in each section. The allocation is often based on factors like:
To confirm the section you’ll be admitted to, contact the school’s admission office directly.
I hope this answer helps you. If you have more queries then feel free to share your questions with us we will be happy to assist you.
Thank you and wishing you all the best for your bright future.
To calculate sec(-585°) we use the periodicity of secant.
The period of the function secant is 360°. Then, sec(x) = sec(x + 360°).
Thus, sec(-585°) = sec(-585° + 360°) = sec(-225°).
We can further simplify,
sec(-225°) = sec(135°).
Then we can apply the following identity, sec(x) = 1/cos(x)
Therefore sec(135°) = 1 / cos(135°).
We already know that cos(135°) = -√2/2.
So, sec(135°) = 1 / -√2 / 2 = -2 / √2 = -√2
Therefore, sec(-585°)= -√2.