if the mean free path of atom is doubled at constant temperature then the pressure of gas will become
Hello!!
According to your question temperature is kept constant and mean free path is doubled thus,
Proceeding-
Solution :
λ∝1/P
When mean free path is doubled, pressure becomes half.
So the answer would be simply p/2.
I really hope this helps you!!
Thank you!!
The mean free path is the distance that a molecule travels between collisions.
Let us denote it with L.
Now , after looking at the formula of mean free path , we can say that pressure is inversely proportional to mean free path.
Therefore , when mean free path of atom is doubled , pressure will become halved .
L =2x , then P= x/2.