Question : What is the value of $\frac{99 \div 33+44 \div 11 \text { of } 4}{24 \div 12–4+3}$?
Option 1: 6
Option 2: 4
Option 3: 1
Option 4: 8
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Correct Answer: 4
Solution : $\frac{99 \div 33+44 \div 11 \text { of } 4}{24 \div 12–4+3}$ $=\frac{99 \div 33+44 \div 44}{2–4+3}$ $=\frac{3+1}{5–4}$ $=4$ Hence, the correct answer is 4.
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