Saveetha Engineering College, Chennai All Questions

Hello,

We know that, as per the Equation of Motion,

s = ut + 0.5 a t^2

So, for first 3 sec.,

10 = 3u + 0.5 x a x 9

So, 3u + 4.5a = 10.............. ( 1 )

Now, for next 4 sec.,

25 = 7u + 0.5 x a x 49

So, 7u + 24.5a = 25............ ( 2 )

Solving ( 1 ) and ( 2 ), we get,

a = 0.12 m/s^2 and u = 3.15 m/s

Now, also as per the Equation of motion,

v = u + at

So, For 8 sec.,

v = ( 3.15 ) + ( 0.12 x 8 )

So, v = 4.11 m/s

Hence, The velocity of object at the end of 8 seconds will be 4.11 m/s

Best Wishes.

Hello,

Given that the distance is directly proportional to the square of time.

So, d ∝ t^2

So, d = k.t^2

Where, k is the constant of proportionality.

Now from first condition,

d = 78m and t = 7 sec.

So, 78 = k. 7^2

So, k = 1.59 = 1.6

Now, d = k. t^2

So, for first four seconds, t = 4sec

So, d = k. 4^2

So, d = 1.6 x 16

So, d = 25.6 m

So, The stone will fall a total distance of 25.6 m in 1st 4 seconds.

Best Wishes.

Using s = ut + 1/2a(t^2),  we can write

100 = 4u  + 8a

=> u + 2a = 25             ------(1)

Also, Since the distance traveled in the next 4 seconds is 140m, the total distance traveled in the 8 seconds is 240 m. So we can write

240 = 8u + 32a

=> u +4a = 30              ------(2)

Solving Eq.1 and 2 we can say,

a = 5/2 m/s/s and u = 20 m/s

Hence the velocity at t=6 sec, is 20 + 5/2*6 = 35m/s.

Hello Aspirant,

Based on this score chances seem less to get a seat in Government colleges under All India quota seats & state quota seats, You can get a seat in private colleges for MBBS programme. Since it is very late to answer your query, I hope you have checked the seat allotment of All India Quota & West Bengal state counselling & also allotted the seat in any of the medical college.

Do let us know if you have any other query.

Good Luck!

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