SPA Delhi All Questions

Hi  Supreeth,

You got 93.408 percentile in JEE main 2 exam, your rank would be approximately in between 7000 to 8000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check your expected rank using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112680, your rank will be around 7400. However as the no. of students in April changes, your rank will change according to that. On the basis of your percentile, you will get only private colleges:

Ansal university

LPU Punjab

Integral university Lucknow

Also, you have to improve your rank in april exam to get SPA Vijaywada. If you secured a rank below 3500, then there will be a great chance to getting an SPA Vijaywada . All the best!!

You can also go through our college predictor to check which colleges you are eligible for through your JEE Mains score. The link for the college predictor is : https://engineering.careers360.com/jee-main-architecture-college-predictor

You can calculate your rank in JEE Main Paper 2 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 (Jan) are around 112679, your rank will be around 1250. However as the no. of students in April changes, your rank will change according to that.

With this rank, there are some chances of getting admission into SPA Delhi. However, you may also apply to some NIT colleges which offer Architecture branch. To check the cutoffs for NITs which offer Architecture branch, you can use the following link:

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

However, to get the list of all Institutes which you may get with this rank, kindly use the college predictor through the link given:

https://engineering.careers360.com/jee-main-architecture-college-predictor

For more information regarding counseling, cutoffs, etc.. you can use the B.Tech companion from the link given below:

https://www.careers360.com/btech-companion

Hii

Last year the closing rank at SPA bhopal was 809. It is expected that it will be in same range this year too.

Your jee rank can be calculated using this formula-

(100-percentile)* number of students appeared/100

That crossponds to be in range 880-1170

So, it seems you have low chance on this percentile.  So, perform better in april .

Hope it helps

Hello Vikas

Last years cut off for SPA bhopal for b. Arch for general category opening and closing rank are as follows:

Opening rank was 183 and closing rank was 870 for general category.

Admission in its undergraduate courses, B.Arch. and B.Plan. will be given on the basis of JEE Main Cutoff.. A total of 75 seats will be filled in SPA Bhopal through JEE Main.

Hey there hope you're doing well.
Dear aspirant, congratulation on scoring a good percentile in the JEE MAIN examination paper 2 for B.arch. As per your percentile you are in the top 2 percentile of students but still cutoffs for paper 2 is very high. You can calculate your rank by the formula
(100- your percentile score)*112679/100.
Also I'm providing you with our college predictor link for getting a better picture of the colleges you can get with this percentile score.
Link- https://engineering.careers360.com/jee-main-architecture-college-predictor.
Also you need to be among the top ranks in your respective category since seats are very limited.Fir getting seats in NITs and SPAs you need to be atleast in top 50 or 100 rank.
Thank you hope this helps you All the Best!

Hey there hope you're doing well.
Dear aspirant, you're at right place for we can provide you with formula for calculating your rank with your percentile score in JEE MAIN examination paper 2.
Formula ( 100- your percentile score)112679/100
Also I'm providing you with our college predictor link to get the colleges you can get with this percentile and percentile to get SPA DELHI.
Link - https://engineering.careers360.com/jee-main-architecture-college-predictor.
Thank you hope this helps you!

Hello Shruthi

As you have mentioned your percentile in JEE MAINS PAPER 2,your expected rank should be 13,127,and with this rank you cannot get NIT because the cut off of NITs is very high,you can check previous year cut off here https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning But don't worry,because there are many other colleges where you can get admission.

You can use college predictor tool to get the result of colleges you can get at this rank from here https://engineering.careers360.com/jee-main-architecture-college-predictor

I hope This Helps

Best Of Luck!!!!

Hello.
You can calculate your expected AIR by using the formula given below:
(100-your total percentile)*112679/ 100
Here 112679 is the number of candidates appeared for the exam in January 'session'.
Using above formula you can calculate your expected AIR which would be : 496.
But in SPA delhi as per the past trends we can analyse that cutoff for general  category goes nearly under 480 ( average for b.arch) and for b.plan it goes nearly under 1200( average ) so , you have decent chances of admission in both if we consider your category .
Now for predicting more college you can refer our college predictor tool from the below link:
https://engineering.careers360.com/jee-main-college-predictor
Best of luck.

Hello

It would be difficult to tell you exactly about the cutoff as it varies every year depending on many factors such as the difficulty level of the exam, number of candidates appearing in the exam, number of seats, etc.

You can refer to the previous year cutoff for reference and to have an idea about the rank required. Last Year's cutoff for admission to Architecture course in School of Architecture and Planning, New Delhi was as follows:

For OBC NCL, Closing rank (round 7) was - 733
For Open category, Closing rank (round 7) was - 768

Good Luck!

Looking towards your percentile score which is 93.408. ..
Your rank can be predicted by the following method:
First of all you need to get the percentage of people ahead of you-
(100- your score).
100-93.408 = 6.592
The number of candidates appeared for January exam were 112679
And the formula to predict your rank is
(100 - your total score) 112679/100
6.592 1126.79 = 7427..
You might get good College in your home state Karnataka..
You can go through the given link to know about which college you might be getting by entering your predicted rank...
https://engineering.careers360.com/jee-main-architecture-college-predictor