NIT Rourkela All Questions

Dear aspirant,

As per my view if I had to consider placements only then of course mnit bhopal and IIIT allahabad would be at a better place if I had to compare between nit Agartala and iiest shibpur.

Nit Agartala is considered to be a decent college not very good or not bad whereas iiest shibpur placements are not very great in case of biotechnology. The placements are very dull. Almost 30-40% are placed from this branch which is very less.

So, IIIT allahabad average package stands somewhere between 18L for cse and for other branches 8-9L atleast. Same in the case for manit bhopal but average package is a bit lower.

Hello Aspirant,

If we go through the analysis of marks Vs Percentile Vs rank for JEE-Main 2020 then according to the percentile mentioned by you in the question your CRL rank is expected to be in the range of 112530 - 126500 , you can check out marks Vs ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

Or

You can also use JEE-Main Rank Predictor to predict your rank :-

https://engineering.careers360.com/jee-main-rank-predictor

As we go through the latest cut-offs of JEE-Main 2020 of JOSAA 6th round then it shows that :-

Closing EWS rank for NIT Rourkela was :-

Food Process Engineering branch - 17025 (Home state quota)

And your EWS rank is expected to be around 17,000

So you have good chances to get NIT Rourkela with Food Process branch.

But yes if you improve your percentile in any further session of JEE-Main like around 32-93 then you might have a shot at some other branches too in NIT Rourkela.

You can check out the latest cut-offs from the link given below :-

https://josaa.nic.in/Result/Result/currentorcr.aspx

Note that the above prediction is made on the basis of latest cut-offs available on official website of JOSAA or CSAB and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.

To have a list of all those colleges which you can get based upon your marks, category, and state you can use JEE-Main College Predictor:-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

If you are preparing for JEE-Main 2021 or 2022 then I would recommend you to check the resources made by our experts to help aspirants like you in the best and smart preparation of JEE-Main 2021 or 2022 :-

https://learn.careers360.com/jee-main-coaching/?utm_source=%20QnA

You can also check out the JEE-Main 2021 qualifying cut-off (expected) for JEE-Advance 2021 from the link given below :-

https://engineering.careers360.com/articles/jee-main-cutoff

I hope this information helps you.

Good Luck!!

Hello,

You need to score the minimum cut off rank to get seat in NIT, Rourkela. Now, this cut off rank changes every year depending on the total number of candidates appeared, difficulty level of examination and total number of seats available etc. The cut off rank for General, OBC-NCL, SC, ST,EWS and PWD category is different and it varies for home state candidates and candidates who are from other states. Taking the previous year cut off in to consideration you need to score approximately 200-220 or above marks if you belong to general category, if you belong to SC/ST category you need to score minimum 120-150 or above marks and if you belong to OBC-NCL category you need to score minimum 150-180 marks or above to have decent chances of getting seat in NIT, Rourkela.

To check the previous year cut off for NIT, Rourkela click on the link below

https://engineering.careers360.com/articles/jee-main-cutoff-for-nit-rourkela

If you are preparing for JEE MAIN you can make enroll in our JEE Main knockout to get help with your preparation

https://learn.careers360.com/knockout-jee-main-april/?icn=jee-main-knockout_landing-page&ici=nav-header_engg

Hi Aspirant,

Computer Science Engineering From VIT is good.The placement here is excellent.The placement percentage stays about more than 98 percent every year for this stream.The highest salary package offered is around 40 LPA, and the minimum salary package offered is around 3 LPA. Most of the companies that come for CSE offer a minimum salary package of 6 LPA and go up to 40 LPA.Internship opportunities are quite good here.Recruitmet takes at renowned companies like  Microsoft, Paypal, Cisco, DE Shaw etc.

Hope it helps!!

Hello,

It would be difficult to predict the cut off for CSAB 2021 round as the cut off depends on the total number of seats available after JoSAA round, total number of candidates participating in CSAB, difficulty level and other factors. So it is not possible to indicate the cut off prior to the counselling but here is the cut off in CSAB 2020 round 1 counselling for admission to Integrated  Master of Science in Chemistry for NIT, Rourkela

Home state

• General:87893
• EWS: 127471
• OBC-NCL; 139375
• ST: 420686

Open state

• General:43568
• EWS: 48759
• OBC-NCL: 53528
• SC: 177557

All the ranks mentions are CRL ranks secured by the candidates belonging to the respective categories. The cut off is subjected to change, it may increase or decrease depending on total number of candidates applied, difficulty level of paper and number of seats available etc.

To check the cut off you can use the link provided

https://admissions.nic.in/csabspl/csabsplresult/result/CurrentORCR.aspx

To know the colleges in which you may get seat you can use our JEE Main college predictor

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Hi

Your profile suggests that your home state is Telangana so you will be eligible for other state quota in NIT Rourkela

With  96.25 percentile

• your rank will be around 38362 - 43125   as per our rank predictor at https://engineering.careers360.com/jee-main-rank-predictor

It is quite difficult to make prediction but yes as per past year trend , you hold a little low chance to get a seat in NIT Rourkela for Chemistry (5 Years, Integrated Master of Science) .

For example,

In 6th round of josaa counselling 2020, closing rank for gender-neutral for general category was 36585 for Chemistry (5 Years, Integrated Master of Science) for gender neutral general category for other state

You can check the same at

https://josaa.nic.in/Result/Result/currentorcr.aspx

Above prediction is on the basis of past year data but  cut off/closing rank for colleges keeps changing every year depending upon many factors like number of students that appeared in the examination, difficulty level of the JEE main question paper for different shifts etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you

Thankyou

Hello aspirant,

Its costs around 90000-100000 per annum but you will get scholarship too.

Fee is different for different streams of M.sc(varies lillte bit).

Scholarship is based on the rank and caste category.

Hope this helps you

All the best for your future

Hi

I am assuming that you belong to general category and your profile suggests that you are from Odisha so you will be eligible for home state quota in NIT Rourkela

This is a bit difficult to predict the marks/percentile/rank required in JEE mains to get a seat as cut off  keeps changing every year  depending upon various factors like  number of students that appeared in the exam, kind of marks obtained by them , toughness level of the jee main examination , number of seats available for the branch you want etc.

But yes,

When we go through previous year trend then ,

In round 6 of josaa counselling 2020 , 64056 was the closing rank for gender neutral for general category for home state in NIT Rourkela and it was for Life Science (5 Years, Integrated Master of Science)

You can check the same at

https://josaa.nic.in/Result/Result/currentorcr.aspx

And to get around 64056 rank, you need at least around 95 percentile as per our rank predictor at

https://engineering.careers360.com/jee-main-rank-predictor

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

If you have any other doubt then you can always reach us to clear them :) we are always available to help you out and guide you

Thankyou

Hii Aspirant,

On based last year 93.5 percentile in Jee Main Feburary  your rank in general should be around 70k - 78k and your rank in EWS category will be around 10k. Under home state quote you may get a chance to get in Nit Rourkela . Nit Rourkela chances depend on the sit avaliablity also.

Hope it helps!!

Hello,

JEE Main 2019 cut off for ECE in NIT Rourkela was:

Home state general: 12594

Home state EWS: 1699

All India General: 5674

All India EWS: 618

So, judging from previous year cut off, you need to score more than 135-140 marks in JEE Main.

Hope it helps!

Good luck!