NIT Rourkela All Questions

Hello,

Last year a candidate belonging to general category with rank 20915 (home state) secured admission to Mechanical Engineering in National Institute of Technology, Rourkela. A with rank 16075 (Other state) belonging to general category secured admission to Mechanical Engineering in National Institute of Technology, Rourkela. Considering the previous year cut off you need to secure rank in between 15000-20000. To secure such rank you need to score 99 percentile or above and you should aim to score minimum 250-260 marks or above in JEE Main. Cut off is subjected to change it may increase of decrease depending on total number of candidates appeared, difficulty level of examination and total number of seats available etc. To check the previous year cut off use the link below

https://josaa.admissions.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

If you are preparing for JEE Main 2022 you may check our JEE Main Knockout package and enroll in it to get help with your preparation

https://learn.careers360.com/knockout-jee-main-april/

Hello aspirant,

Looking at the previous year JEE mains Cutoff trends and analytics, you will need a minimum marks of around 120-140 in JEE mains to get admission in NIT rourkela, as a SC Category Students, to be on the safer side. Fo general Category it's 150+ marks in JEE mains to get NIT Rourkela.

Further, please note that the above mentioned prediction is totally based on the previous year JEE mains Cutoff trends and it may vary as it bound to change every year, The JEE mains Cutoff depends on various factors like : Difficulty level of the paper, previous year Cutoff trends, Number of aspirants appearing, etc.

Further, to know more about the JEE mains cutoff you can follow the below mentioned link to know more about it : https://engineering.careers360.com/articles/jee-main-cutoff

I hope that this will help.

hello aspirant...

hope you are doing good.

it depends. but the answer will be yes. just because it is IIT people assume that it is better that NITs but NIT rourkela is better than some IITs as it is In the year 2020, NIRF has NIT Rourkela ranked 19 and IIT Bhubaneswar ranked 26. As a result, NIT Rourkela is ranked higher than IIT Bhubaneswar.

NIT Rourkela has improved infrastructure, overall development, exposure, and curriculum, and now that it is one of three NITs, there is even more to look forward to.

hence, NIT Rourkela is better than some IITs.

hope this information helps you...

All the best.

Hi

Assuming you from general category.

Your profile suggests that your home state is Odisha

Making  prediction is difficult as  cutoff  depends upon various factors like :-

-----------) number of students/ candidates  that appeared in the  jee main exam,

-----------) number of available seats,

-----------) jee main examination difficulty level.

-----------) the branch you want,

-----------) the category you belong etc.

But yes,

When we go through previous year trend then,

In 6th round of josaa counselling 2021

----------) Under home state, closing rank was :-

• NIT Rourkela  :- 59726  rank and it was for Ceramic Engineering and M.Tech Industrial Ceramic (5 Years, Bachelor and Master of Technology (Dual Degree))

And for such  rank , you need  at least around 94 .5 percentile in jee main

You can check the same at:-

JOSAA 2021:- https://josaa.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

Or

For previous years cut offs of top colleges like NITs, IIITs , you can also refer our page at :-

NITs :- https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

IIITs:- https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits

• Jee main marks vs rank vs percentile :-:- https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

• JEE main rank:- predictor:-predictor:- https://engineering.careers360.com/jee-main-rank-predictor

• JEE main college predictor, to know the colleges you can get admission in:- https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To help you  further,

To give an idea of jee main 2022 qualifying cut off ,

Minimum percentile in jee main 2021 to qualify it to be eligible for jee advanced is given below :-

--------) general :-87.8992241 percentile

--------) EWS:- 66.2214845 percentile

--------) OBC-NCL :- 68.0234447 percentile

--------) SC :- 46.8825338 percentile

--------) ST:- 34.6728999 percentile

--------) PWD :- 0.0096375 percentile

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

To enhance your performance in jee main, you can go for jee main rank booster course for which link is given below:-

https://learn.careers360.com/jee-main-rank-booster/

Thankyou

Hi

NIT Rourkela has a campus  of 645 acres.

To help you further,

Here's some other information / detail about it:-

--------------------) it is a government college

--------------------)it is Institute of national importance

--------------------)ranked 20th in engineering in nirf 2021

--------------------)it has been accredited by NAAC

--------------------) it is co-ed

--------------------) it was established in the year 1961

--------------------) There are a total of all around 215 faculties

It offers various courses like

--------------------) Btech

--------------------) Mtech

--------------------) Msc

--------------------) Phd

--------------------) Btech-Mtech integrated

For detailed information , you can check out our page   , the link for the same is provided below:-

https://www.careers360.com/university/national-institute-of-technology-rourkela

>>>>>>> Admission process for NIT Rourkela for btech

---------------------------) Appear in jee main

To be eligible for appearing in jee main for BE/Btech, you must have passed or should be appearing for  12th/equivalent with Physics and   Mathematics as compulsory subjects along with any one of :-

----)Chemistry

-----)Biotechnology

-----)Biology

----) Technical Vocational subject.

You are eligible for JEE main examination for only consecutive three years starting from the year of appearing for 12th /equivalent examination. You can get complete eligibility criteria at:-

https://engineering.careers360.com/articles/jee-main-eligibility-criteria

---------------------------) Participate in josaa counselling.

Detailed information about counselling is available at

https://engineering.careers360.com/articles/josaa-counselling

---------------------------) In the josaa counselling, fill Nit rourkela in choice filling, you can get a seat in NIT rourkela on the basis of your rank in JEE Main examination and the category you belong to .

• To get an idea of JEE main cut off for different NITs checkout:- https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

---------------------------) Then you have to report to the college and get your documents verified.

---------------------------) After document verification, finally you can get admission in NIT Rourkela

Thank you

Dear aspirant,

If you were to take my opinion then you should opt for nit Rourkela because its ranking is better both in management and engineering and it is also more renowned than mnit Jaipur.

In terms of placements both these nits are at par because the average package is not much as compared to a top B school. The average package in management is around 5-6L per annum in both the nits so i would recommend you to kindly if possible opt for other college which has strong alumini network in management and has good placement stats.

it is quite difficult to tell only about one is specialisation that's why I am mentioning the the placement details of overall courses. The National Institute of Technology Rourkela placement details of master of technology are as follows:

1. There are 178 job offers made in the year 2020 for master of technology students.
2. The lowest salary package which was offered in the institute was 2.40 lacs per annum.
3. The average placement package which was offered in the institute was 8.89 lacs per annum
4. The highest placement package which was offered in the institute was lacs per annum.
5. Out of 178 offers 42 placement offers were made for electronic systems and communication engineering students.

Read more:

https://www.google.com/url?sa=t&source=web&rct=j&url=https://www.careers360.com/university/national-institute-of-technology-rourkela/placement&ved=2ahUKEwjsh4zY8rH2AhUdslYBHYyLCeIQFnoECAkQAQ&usg=AOvVaw0cdt79Q1nu-bb1zqE6CYZE

Hello Aspirant,

As we go through the latest cut-off of 2021 then it shows that the closing CRL rank was 9349 for Computer Science and Engineering branch in NIT Rourkela under Home state quota for Open/Un-reserved/General category.

You can check out the latest cut-offs from the link given below :-

https://josaa.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

Now to secure such rank you should have your JEE-Main  score at least 180+ marks out of 300 and percentile against this should be around 99.2+.

You can check out marks Vs ranks Vs Percentile from the link given below :-

https://engineering.careers360.com/articles/jee-main-marks-vs-percentile

Or

You can also use JEE-Main Rank Predictor to predict your rank :-

https://engineering.careers360.com/jee-main-rank-predictor

Note that the above prediction is made on the basis of latest cut-offs available on official website of JOSAA or CSAB and the cut-offs are bound to change every year depending upon various factors such as the number of candidates appearing in an examination, the number of candidates qualifying an examination, difficulty level of the paper, and so on.

To have a list of all those colleges which you can get based upon your score, category, and state you can use JEE-Main College Predictor :-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

As you are preparing for JEE-Main then I would recommend you to check the resources made by our experts to help aspirants like you in the best and smart preparation of JEE-Main :-

https://learn.careers360.com/jee-main-coaching/?utm_source=%20QnA

I hope this information helps you.

Good Luck!!